eswube wrote: * | October 14th, 2022, 6:44 am |
I would say, that
by the logic of SB style shading there
has to be lens-shaped part on an object of spherical-ish shape, because (assuming we're not talking about object simply too small to fit 3 shades into it) immediate "switch" from highlight to dark could happen only when said switch is abrupt, and here it's not the case. Also, the source of light is in front of the bow, so the "not darkened" (highlight and basic) area goes past ("below") the "central point" of the cross section - meaning, that the centre point of the circle of the drawing is also "shine upon".
The way You shaded it (without the lens) IMHO could be relevant if the source of light was
above the ship, not
above and in front of.
Well, if You're replying with "20 second edit is to blame", then my original drawing was also "20 second...", and yet it didn't deterred You from starting this whole discussion about it's supposedly horrible errors.
Well, to be fair, it was not my intention to make this a whole discussion. My point about the 20 second edit was that we should not find new issues with our 20 second edits every time we try to quickly explain something to each other
The important factor is me pointing out a single point and you saying you always do it this way so we should discuss it. Then my example not being symmetrical is a different subject that is in my opinion not worth it being discussed, as that is something I try to avoid doing in any real drawings.
That said. Could you please explain to me where this lens-shaped thing comes from? Was that what you got from my explanation because then I must have explained things wrong or at least not clearly.
My thought is this: if the cross section remains constant (let's use a perfectly circular shape in this example) the shaded area relative to the total cross section height remains constant. In this case, it is a circle, so the 45 degree shading rules state that the middle 70.7% is the base shade and the bottom and top 14.7% are highlighted and shaded. This means between the black line on your submarine, at the straight section, 49 pixels should be base shade and the bottom and top 10 pixels should be shaded. This amount decreases as the cross section does, similar to how this happens in the stern of your example. (I know the numbers don't add up to 70 but here you run into trouble with half pixels, I calculated this in excel and just let it round to the nearest whole pixel)
Using this method, the cross sections at the very front are 4,14,18,22,24 etc on your submarines bow; so the shaded area at the bottom would be 1,2,3,3,4 pixels. And using that method, we see that even at the very front, an base shaded area of 2 (technically even 2.8, as the shaded areas are technically 0.6 pixels) pixels wide remains. Even if the cross section would only be a single pixel, that pixel would be 70.7% base shade.
Do I think something like the above excel sheet results should be made for every drawing? Certainly not. We work as artists and there is room for interpretation. But using the 45 degree shading rule, on a circular or near circular cross section, even with an big bulbous front, the dark shade and the highlight can never meet as there is always an area of base shade in between that is more then twice as big as the shaded and highlighted areas combined. Yes, in reality, those shades would meet as the cross section reaches zero, but we can only draw whole pixels
And a very small note, on hull shading it is common to ignore the light coming from the front as that would make it impossible to accurately represent any shape. The one exception is the very clear case of transom sterns which are shaded, and similarly some flat bows can get a lighter colour to match the superstructure shading...... but the gentle curving shape of a ships hull is extremely hard to shade with light coming from the front, made even more complicated by round shapes..... as heuhen's image proves. I think it would be beyond the spirit of shipbucket to go that way